The new film “Ralph Breaks the Internet” could also be on pace to break a box office record. The sequel to “Wreck-It Ralph” could score between $85 million to $90 million in box office revenue for the Thanksgiving weekend.
According to Comicbook’s report, it will need to hit $93.7 million or better to break the five-day weekend record. That is currently held by Disney’s “Frozen” which tallied $93.6 million over the holiday period back in 2013. It went on to earn over $1.2 billion at the box office and became “highest-grossing animated film” ever.
In 2012, the “Wreck-It Ralph” movie scored $49 million over its three-day opening. It would go on to take in $189 million domestically and $471 million worldwide by the time its run was over at theaters. It appears to have captured the magic of the first film and has families heading out to see it for the holiday season.
The sequel brings back actor John C. Reilly in the lead role and comedian/actress Sara Silverman to reprise her role. Other’s returning to the sequel are Ed O’Neill (“Modern Family”) and Jane Lynch (“Glee”). Newcomers in the film include Gal Gadot (“Wonder Woman”) and Taraji P. Henson (“Empire”).
Reilly is the voice of video game villain Ralph. His friend Vanellope von Schweetz (Silverman) is back to help search the internet to find a replacement part for her new game. Along the way, they bump into characters such as an entrepreneur named Yesss (Henson), Shank (Gadot), and Fix-It Felix (Jack McBrayer).
As of Friday, the Box Office Mojo website which keeps track of box office revenue, has “Wreck-It Ralph” sequel estimated as taking in over $21.7 million as of Friday (Nov. 23). Right behind are two more sequels as “Creed II” has tallied an estimated $14.129 million and “Fantastic Beasts 2,” over $11.8 million so far.
“Ralph Breaks the Internet” is rated PG and has a run time of an hour and 56 minutes. It also comes with a “certified fresh” rating via Rotten Tomatoes at 86 percent out out a possible 100 percent based on an aggregate score of critical reviews.